What are the solutions to the equation -x^2-6x+1=0 ?

The solutions to the equation -x^2-6x+1=0 are x=-3-sqrt(10),x=sqrt(10)-3

Find the zeros of -x^2-6x+1=0

The zeros of -x^2-6x+1=0 are x=-3-sqrt(10),x=sqrt(10)-3

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- x^{2} - 6 x + 1 = 0

x = - 3 - 10, x = 10 - 3

Decimal Notation

x = - 6.16227 \dots, x = 0.16227 \dots

Solution steps

- x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 1 = 210

x_{1, 2} = \frac{- ( - 6 ) \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 10}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 10}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 10}{2 ( - 1 )} : - 3 - 10

x = \frac{- ( - 6 ) - 2 10}{2 ( - 1 )} : 10 - 3

The solutions to the quadratic equation are:

x = - 3 - 10, x = 10 - 3

d^{3} - 8

∣ 3 x - 1 ∣ - 2 = 2

\frac{x - 6}{2 x + 9} \geq 1

x^{2} + 6 x + 5 > 0

1 - x + x^{2} = 0

What are the solutions to the equation -x^2-6x+1=0 ?
The solutions to the equation -x^2-6x+1=0 are x=-3-sqrt(10),x=sqrt(10)-3
Find the zeros of -x^2-6x+1=0
The zeros of -x^2-6x+1=0 are x=-3-sqrt(10),x=sqrt(10)-3