What are the solutions to the equation 2x^2-3x-3=x+1 ?

The solutions to the equation 2x^2-3x-3=x+1 are x=1+sqrt(3),x=1-sqrt(3)

Find the zeros of 2x^2-3x-3=x+1

The zeros of 2x^2-3x-3=x+1 are x=1+sqrt(3),x=1-sqrt(3)

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2 x^{2} - 3 x - 3 = x + 1

x = 1 + 3, x = 1 - 3

Decimal Notation

x = 2.73205 \dots, x = - 0.73205 \dots

Solution steps

2 x^{2} - 3 x - 3 = x + 1

Move

1

to the left side

2 x^{2} - 3 x - 4 = x

Move

x

to the left side

2 x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 4) = 43

x_{1, 2} = \frac{- ( - 4 ) \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 3}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 3}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 3}{2 \cdot 2} : 1 + 3

x = \frac{- ( - 4 ) - 4 3}{2 \cdot 2} : 1 - 3

The solutions to the quadratic equation are:

x = 1 + 3, x = 1 - 3

15 x (x - 5) < 3 (5 x - 1) (x - 6)

2^{- \frac{1}{2}}

25 - 64 u^{2}

\frac{1}{3 - i}

27 r^{2} - 48

What are the solutions to the equation 2x^2-3x-3=x+1 ?
The solutions to the equation 2x^2-3x-3=x+1 are x=1+sqrt(3),x=1-sqrt(3)
Find the zeros of 2x^2-3x-3=x+1
The zeros of 2x^2-3x-3=x+1 are x=1+sqrt(3),x=1-sqrt(3)