What are the solutions to the equation 15y=25y^2 ?

The solutions to the equation 15y=25y^2 are y=0,y= 3/5

Find the zeros of 15y=25y^2

The zeros of 15y=25y^2 are y=0,y= 3/5

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15 y = 25 y^{2}

y = 0, y = \frac{3}{5}

Decimal Notation

y = 0, y = 0.6

Solution steps

15 y = 25 y^{2}

Move

25 y^{2}

to the left side

15 y - 25 y^{2} = 0

Factor

15 y - 25 y^{2} : - 5 y (5 y - 3)

- 5 y (5 y - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 5 y - 3 = 0

Solve

5 y - 3 = 0 : y = \frac{3}{5}

The solutions to the quadratic equation are:

y = 0, y = \frac{3}{5}

(∣ x + 4 ∣^{2} - 25) (x^{2} - 9) \leq 0

3 (x + 4) = 18

- 4 ∣ 1 - x ∣ < - 16

x - 4 > 3 x + 8

\frac{2}{3} x + 9 < 5

What are the solutions to the equation 15y=25y^2 ?
The solutions to the equation 15y=25y^2 are y=0,y= 3/5
Find the zeros of 15y=25y^2
The zeros of 15y=25y^2 are y=0,y= 3/5