What are the solutions to the equation x^2-8x=72 ?

The solutions to the equation x^2-8x=72 are x=2(2+sqrt(22)),x=2(2-sqrt(22))

Find the zeros of x^2-8x=72

The zeros of x^2-8x=72 are x=2(2+sqrt(22)),x=2(2-sqrt(22))

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x^{2} - 8 x = 72

x = 2 (2 + 22), x = 2 (2 - 22)

Decimal Notation

x = 13.38083 \dots, x = - 5.38083 \dots

Solution steps

x^{2} - 8 x = 72

Move

72

to the left side

x^{2} - 8 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 72) = 422

x_{1, 2} = \frac{- ( - 8 ) \pm 4 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 22}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 22}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 22}{2 \cdot 1} : 2 (2 + 22)

x = \frac{- ( - 8 ) - 4 22}{2 \cdot 1} : 2 (2 - 22)

The solutions to the quadratic equation are:

x = 2 (2 + 22), x = 2 (2 - 22)

6 + 210

b^{2} + 36 = 0

2 x + 3 < 21 and - 7 x + 3 < - 4

\frac{a ^{6}}{a ^{- 3}}

x^{4} + 125 x

What are the solutions to the equation x^2-8x=72 ?
The solutions to the equation x^2-8x=72 are x=2(2+sqrt(22)),x=2(2-sqrt(22))
Find the zeros of x^2-8x=72
The zeros of x^2-8x=72 are x=2(2+sqrt(22)),x=2(2-sqrt(22))