What are the solutions to the equation 8x^2+x-1=0 ?

The solutions to the equation 8x^2+x-1=0 are x=(-1+sqrt(33))/(16),x=(-1-sqrt(33))/(16)

Find the zeros of 8x^2+x-1=0

The zeros of 8x^2+x-1=0 are x=(-1+sqrt(33))/(16),x=(-1-sqrt(33))/(16)

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8 x^{2} + x - 1 = 0

x = \frac{- 1 + 33}{16}, x = \frac{- 1 - 33}{16}

Decimal Notation

x = 0.29653 \dots, x = - 0.42153 \dots

Solution steps

8 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

1^{2} - 4 \cdot 8 (- 1) = 33

x_{1, 2} = \frac{- 1 \pm 33}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 1 + 33}{2 \cdot 8}, x_{2} = \frac{- 1 - 33}{2 \cdot 8}

x = \frac{- 1 + 33}{2 \cdot 8} : \frac{- 1 + 33}{16}

x = \frac{- 1 - 33}{2 \cdot 8} : \frac{- 1 - 33}{16}

The solutions to the quadratic equation are:

x = \frac{- 1 + 33}{16}, x = \frac{- 1 - 33}{16}

\frac{2}{4} + \frac{3}{4} + 1

10 x^{2} + 7 x - 12

\frac{7 - 3 x}{2} \leq 1

2 x^{2} - x - 28

14 g h - 18 h

What are the solutions to the equation 8x^2+x-1=0 ?
The solutions to the equation 8x^2+x-1=0 are x=(-1+sqrt(33))/(16),x=(-1-sqrt(33))/(16)
Find the zeros of 8x^2+x-1=0
The zeros of 8x^2+x-1=0 are x=(-1+sqrt(33))/(16),x=(-1-sqrt(33))/(16)