What are the solutions to the equation 4x^2+24x=-36 ?

The solutions to the equation 4x^2+24x=-36 are x=-3

Find the zeros of 4x^2+24x=-36

The zeros of 4x^2+24x=-36 are x=-3

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4 x^{2} + 24 x = - 36

x = - 3

Solution steps

4 x^{2} + 24 x = - 36

Move

36

to the left side

4 x^{2} + 24 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 36}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 36 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 4}

x = \frac{- 24}{2 \cdot 4}

\frac{- 24}{2 \cdot 4} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

∣ x ∣ + 3 = 12

- 2 (u + 6) + 6 u = 4 (u - 3)

19 g + 2 - 15 g - 8

- 7 x + 8 = 57

8 x^{2} y - 20 x^{2} - 12 y + 30

What are the solutions to the equation 4x^2+24x=-36 ?
The solutions to the equation 4x^2+24x=-36 are x=-3
Find the zeros of 4x^2+24x=-36
The zeros of 4x^2+24x=-36 are x=-3