What are the solutions to the equation 3v^2-18v=0 ?

The solutions to the equation 3v^2-18v=0 are v=6,v=0

Find the zeros of 3v^2-18v=0

The zeros of 3v^2-18v=0 are v=6,v=0

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3 v^{2} - 18 v = 0

v = 6, v = 0

Solution steps

3 v^{2} - 18 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 0 = 18

v_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- ( - 18 ) + 18}{2 \cdot 3}, v_{2} = \frac{- ( - 18 ) - 18}{2 \cdot 3}

v = \frac{- ( - 18 ) + 18}{2 \cdot 3} : 6

v = \frac{- ( - 18 ) - 18}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

v = 6, v = 0

lo g_{e} (e)

(9 r^{4})^{0.5}

6 (3 x + 1) - 30 = 3 (2 x - 4)

x^{3} - 11 x^{2} + 16 x + 84

\frac{500}{5}

What are the solutions to the equation 3v^2-18v=0 ?
The solutions to the equation 3v^2-18v=0 are v=6,v=0
Find the zeros of 3v^2-18v=0
The zeros of 3v^2-18v=0 are v=6,v=0