What are the solutions to the equation 12x^2+14x-20=0 ?

The solutions to the equation 12x^2+14x-20=0 are x= 5/6 ,x=-2

Find the zeros of 12x^2+14x-20=0

The zeros of 12x^2+14x-20=0 are x= 5/6 ,x=-2

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12 x^{2} + 14 x - 20 = 0

x = \frac{5}{6}, x = - 2

Decimal Notation

x = 0.83333 \dots, x = - 2

Solution steps

12 x^{2} + 14 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 12 ( - 20 )}{2 \cdot 12}

1 4^{2} - 4 \cdot 12 (- 20) = 34

x_{1, 2} = \frac{- 14 \pm 34}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 14 + 34}{2 \cdot 12}, x_{2} = \frac{- 14 - 34}{2 \cdot 12}

x = \frac{- 14 + 34}{2 \cdot 12} : \frac{5}{6}

x = \frac{- 14 - 34}{2 \cdot 12} : - 2

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - 2

\frac{\frac{a + 6}{c}}{\frac{2 a + 6}{2 c}}

x^{\frac{2}{3}} \cdot x

3 k < 6

x^{2} - 3 x - 18

3 x - \frac{1}{2} = \frac{3}{2}

What are the solutions to the equation 12x^2+14x-20=0 ?
The solutions to the equation 12x^2+14x-20=0 are x= 5/6 ,x=-2
Find the zeros of 12x^2+14x-20=0
The zeros of 12x^2+14x-20=0 are x= 5/6 ,x=-2