What are the solutions to the equation 3x^2+24x+56=8 ?

The solutions to the equation 3x^2+24x+56=8 are x=-4

Find the zeros of 3x^2+24x+56=8

The zeros of 3x^2+24x+56=8 are x=-4

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3 x^{2} + 24 x + 56 = 8

x = - 4

Solution steps

3 x^{2} + 24 x + 56 = 8

Move

8

to the left side

3 x^{2} + 24 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 48}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 48 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 3}

x = \frac{- 24}{2 \cdot 3}

\frac{- 24}{2 \cdot 3} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

9^{\frac{1}{3}} \cdot 9^{\frac{1}{6}}

4 x - 2 x^{2} = 1

- 3 x + 7 = 21

\frac{2 X}{7} - 5 \geq 7

x (1) = 1.5 (1)^{3} + 3 (1) - 5

What are the solutions to the equation 3x^2+24x+56=8 ?
The solutions to the equation 3x^2+24x+56=8 are x=-4
Find the zeros of 3x^2+24x+56=8
The zeros of 3x^2+24x+56=8 are x=-4