What are the solutions to the equation -2x^2+5x+12=0 ?

The solutions to the equation -2x^2+5x+12=0 are x=-3/2 ,x=4

Find the zeros of -2x^2+5x+12=0

The zeros of -2x^2+5x+12=0 are x=-3/2 ,x=4

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- 2 x^{2} + 5 x + 12 = 0

x = - \frac{3}{2}, x = 4

Decimal Notation

x = - 1.5, x = 4

Solution steps

- 2 x^{2} + 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 12}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 12 = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 ( - 2 )}, x_{2} = \frac{- 5 - 11}{2 ( - 2 )}

x = \frac{- 5 + 11}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 5 - 11}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 4

\frac{1}{2} (c - 2) + \frac{1}{4} (2 c + 1) = \frac{5}{4}

- x^{2} + 2 x y - y^{2}

16 x^{4} - y^{4}

\frac{4}{5} x + \frac{6}{5} = - \frac{2}{5}

\frac{- 4}{3} = \frac{x}{6}

What are the solutions to the equation -2x^2+5x+12=0 ?
The solutions to the equation -2x^2+5x+12=0 are x=-3/2 ,x=4
Find the zeros of -2x^2+5x+12=0
The zeros of -2x^2+5x+12=0 are x=-3/2 ,x=4