What are the solutions to the equation y^2+1/2 y=-1/16 ?

The solutions to the equation y^2+1/2 y=-1/16 are y=-1/4

Find the zeros of y^2+1/2 y=-1/16

The zeros of y^2+1/2 y=-1/16 are y=-1/4

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y^{2} + \frac{1}{2} y = - \frac{1}{16}

y = - \frac{1}{4}

Decimal Notation

y = - 0.25

Solution steps

y^{2} + \frac{1}{2} y = - \frac{1}{16}

Find Least Common Multiplier of

2, 16 : 16

Multiply by LCM=

16

y^{2} \cdot 16 + \frac{1}{2} y \cdot 16 = - \frac{1}{16} \cdot 16

Simplify

16 y^{2} + 8 y = - 1

Move

1

to the left side

16 y^{2} + 8 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 16 \cdot 1}{2 \cdot 16}

8^{2} - 4 \cdot 16 \cdot 1 = 0

y_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 16}

y = \frac{- 8}{2 \cdot 16}

\frac{- 8}{2 \cdot 16} = - \frac{1}{4}

y = - \frac{1}{4}

The solution to the quadratic equation is:

y = - \frac{1}{4}

\frac{1}{2} x - 9 > 1

5 (2) + 2 y = 10

\frac{x}{5} + 1 = 7

9^{\frac{1}{2}} \cdot 9^{\frac{1}{2}}

2 x + 4 \geq 10

What are the solutions to the equation y^2+1/2 y=-1/16 ?
The solutions to the equation y^2+1/2 y=-1/16 are y=-1/4
Find the zeros of y^2+1/2 y=-1/16
The zeros of y^2+1/2 y=-1/16 are y=-1/4