What are the solutions to the equation 4x^2+13x-75=0 ?

The solutions to the equation 4x^2+13x-75=0 are x=3,x=-25/4

Find the zeros of 4x^2+13x-75=0

The zeros of 4x^2+13x-75=0 are x=3,x=-25/4

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4 x^{2} + 13 x - 75 = 0

x = 3, x = - \frac{25}{4}

Decimal

x = 3, x = - 6.25

Solution steps

4 x^{2} + 13 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 4 ( - 75 )}{2 \cdot 4}

1 3^{2} - 4 \cdot 4 (- 75) = 37

x_{1, 2} = \frac{- 13 \pm 37}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 13 + 37}{2 \cdot 4}, x_{2} = \frac{- 13 - 37}{2 \cdot 4}

x = \frac{- 13 + 37}{2 \cdot 4} : 3

x = \frac{- 13 - 37}{2 \cdot 4} : - \frac{25}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{25}{4}

- 2 \leq 3 (2 y - 1) \leq 7

\frac{k}{k ^{5}}

27 - \frac{1}{8} y^{9}

8 x^{- 3}

(4 x - 2)^{2} - 4 (4 x - 2) + 3 = 0

What are the solutions to the equation 4x^2+13x-75=0 ?
The solutions to the equation 4x^2+13x-75=0 are x=3,x=-25/4
Find the zeros of 4x^2+13x-75=0
The zeros of 4x^2+13x-75=0 are x=3,x=-25/4