What is |(x+2)(x+2)|<2(2-x) ?

The solution to |(x+2)(x+2)|<2(2-x) is -6<x<0

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|(x+2)(x+2)|<2(2-x)

∣ (x + 2) (x + 2) ∣ < 2 (2 - x)

- 6 < x < 0

Interval Notation

(- 6, 0)

Solution steps

∣ (x + 2) (x + 2) ∣ < 2 (2 - x)

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

- 6 < x < 0

2 p > - 4

v^{2} - 9

20 z^{2} + z - 1

3 n^{2} + 30 n + 75

(\frac{7}{9})^{2}