What is ((3rs^2t^4)^2)/(21r^2s^3t^{11)} ?

The solution to ((3rs^2t^4)^2)/(21r^2s^3t^{11)} is (3s)/(7t^3)

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simplify ((3rs^2t^4)^2)/(21r^2s^3t^{11)}

simplify

\frac{( 3 r s ^{2} t ^{4} ) ^{2}}{21 r ^{2} s ^{3} t ^{11}}

\frac{3 s}{7 t ^{3}}

Solution steps

\frac{( 3 r s ^{2} t ^{4} ) ^{2}}{21 r ^{2} s ^{3} t ^{11}}

Simplify

(3 r s^{2} t^{4})^{2} : 3^{2} r^{2} s^{4} t^{8}

= \frac{3 ^{2} r ^{2} s ^{4} t ^{8}}{21 r ^{2} s ^{3} t ^{11}}

Factor the number:

21 = 3 \cdot 7

= \frac{3 ^{2} r ^{2} s ^{4} t ^{8}}{3 \cdot 7 r ^{2} s ^{3} t ^{11}}

\frac{3 ^{2}}{3} = 3

= \frac{3 r ^{2} s ^{4} t ^{8}}{7 r ^{2} s ^{3} t ^{11}}

Cancel the common factor:

r^{2}

= \frac{3 s ^{4} t ^{8}}{7 s ^{3} t ^{11}}

Simplify

\frac{s ^{4}}{s ^{3}} : s

= \frac{3 s t ^{8}}{7 t ^{11}}

Simplify

\frac{t ^{8}}{t ^{11}} : \frac{1}{t ^{3}}

= \frac{3 s}{7 t ^{3}}

7^{\frac{4}{3}}

- 6 z = 72

5 x^{2} + 21 x - 20 = 0

12 x^{2} - 8 = 0

2 a = 63

What is ((3rs^2t^4)^2)/(21r^2s^3t^{11)} ?
The solution to ((3rs^2t^4)^2)/(21r^2s^3t^{11)} is (3s)/(7t^3)