What are the solutions to the equation -x^2=5x-14 ?

The solutions to the equation -x^2=5x-14 are x=-7,x=2

Find the zeros of -x^2=5x-14

The zeros of -x^2=5x-14 are x=-7,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} = 5 x - 14

x = - 7, x = 2

Solution steps

- x^{2} = 5 x - 14

Move

14

to the left side

- x^{2} + 14 = 5 x

Move

5 x

to the left side

- x^{2} + 14 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 5 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 14}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 14 = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 9}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 9}{2 ( - 1 )} : - 7

x = \frac{- ( - 5 ) - 9}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 7, x = 2

6 x^{3} + 21 x^{2} + 15 x

\frac{2}{3} x - 5 = \frac{1}{2} x - 3

(\frac{x ^{3}}{x ^{- 1}})^{- \frac{1}{4}}

\frac{z}{5} + 3 = 35

49 b^{2} + 70 b + 25

What are the solutions to the equation -x^2=5x-14 ?
The solutions to the equation -x^2=5x-14 are x=-7,x=2
Find the zeros of -x^2=5x-14
The zeros of -x^2=5x-14 are x=-7,x=2