What are the solutions to the equation g^2+5g=150 ?

The solutions to the equation g^2+5g=150 are g=10,g=-15

Find the zeros of g^2+5g=150

The zeros of g^2+5g=150 are g=10,g=-15

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g^{2} + 5 g = 150

g = 10, g = - 15

Solution steps

g^{2} + 5 g = 150

Move

150

to the left side

g^{2} + 5 g - 150 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 150 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 150) = 25

g_{1, 2} = \frac{- 5 \pm 25}{2 \cdot 1}

Separate the solutions

g_{1} = \frac{- 5 + 25}{2 \cdot 1}, g_{2} = \frac{- 5 - 25}{2 \cdot 1}

g = \frac{- 5 + 25}{2 \cdot 1} : 10

g = \frac{- 5 - 25}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

g = 10, g = - 15

d^{2} - 16 d + 63

∣ x - 3 ∣ = ∣ 5 ∣ + ∣ - 7 ∣

m^{2} + 10 m + 25

\frac{2}{3} 3^{\frac{3}{2}}

x - (4 x - 1) \leq - 5

What are the solutions to the equation g^2+5g=150 ?
The solutions to the equation g^2+5g=150 are g=10,g=-15
Find the zeros of g^2+5g=150
The zeros of g^2+5g=150 are g=10,g=-15