What are the solutions to the equation -45d^2+4d-1=0 ?

The solutions to the equation -45d^2+4d-1=0 are d= 2/45-i(sqrt(41))/(45),d= 2/45+i(sqrt(41))/(45)

Find the zeros of -45d^2+4d-1=0

The zeros of -45d^2+4d-1=0 are d= 2/45-i(sqrt(41))/(45),d= 2/45+i(sqrt(41))/(45)

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- 45 d^{2} + 4 d - 1 = 0

d = \frac{2}{45} - i \frac{41}{45}, d = \frac{2}{45} + i \frac{41}{45}

Solution steps

- 45 d^{2} + 4 d - 1 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 45 ) ( - 1 )}{2 ( - 45 )}

Simplify

4^{2} - 4 (- 45) (- 1) : 241 i

d_{1, 2} = \frac{- 4 \pm 2 41 i}{2 ( - 45 )}

Separate the solutions

d_{1} = \frac{- 4 + 2 41 i}{2 ( - 45 )}, d_{2} = \frac{- 4 - 2 41 i}{2 ( - 45 )}

d = \frac{- 4 + 2 41 i}{2 ( - 45 )} : \frac{2}{45} - i \frac{41}{45}

d = \frac{- 4 - 2 41 i}{2 ( - 45 )} : \frac{2}{45} + i \frac{41}{45}

The solutions to the quadratic equation are:

d = \frac{2}{45} - i \frac{41}{45}, d = \frac{2}{45} + i \frac{41}{45}

∣ - 2 x ∣ = 8

∣ 7 x - 6 ∣ \leq 29

2 - 5

3 x^{2} + 3

2 x^{2} - 20 x^{5}

What are the solutions to the equation -45d^2+4d-1=0 ?
The solutions to the equation -45d^2+4d-1=0 are d= 2/45-i(sqrt(41))/(45),d= 2/45+i(sqrt(41))/(45)
Find the zeros of -45d^2+4d-1=0
The zeros of -45d^2+4d-1=0 are d= 2/45-i(sqrt(41))/(45),d= 2/45+i(sqrt(41))/(45)