What is the answer to 2-(3-2(x+1))=3x+2(x-(3+2x)) ?

The answer to 2-(3-2(x+1))=3x+2(x-(3+2x)) is x=-7

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2-(3-2(x+1))=3x+2(x-(3+2x))

2 - (3 - 2 (x + 1)) = 3 x + 2 (x - (3 + 2 x))

x = - 7

Solution steps

2 - (3 - 2 (x + 1)) = 3 x + 2 (x - (3 + 2 x))

Expand

2 - (3 - 2 (x + 1)) : 2 x + 1

Expand

3 x + 2 (x - (3 + 2 x)) : x - 6

2 x + 1 = x - 6

Move

1

to the right side

2 x = x - 7

Move

x

to the left side

x = - 7

x y - 2 x - 3 y + 6

5 (x - 3) = 10

(x - 9)^{2} = 64

2 x^{3} + 6 x^{2} - 56 x

3 x^{2} - 18 x

What is the answer to 2-(3-2(x+1))=3x+2(x-(3+2x)) ?
The answer to 2-(3-2(x+1))=3x+2(x-(3+2x)) is x=-7
Solve for x: 2-(3-2(x+1))=3x+2(x-(3+2x))
The solution is x=-7