What are the solutions to the equation 0=-0.01x^2+x+3 ?

The solutions to the equation 0=-0.01x^2+x+3 are x=-10(2sqrt(7)-5),x=10(5+2sqrt(7))

Find the zeros of 0=-0.01x^2+x+3

The zeros of 0=-0.01x^2+x+3 are x=-10(2sqrt(7)-5),x=10(5+2sqrt(7))

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0 = - 0.01 x^{2} + x + 3

x = - 10 (27 - 5), x = 10 (5 + 27)

Decimal Notation

x = - 2.91502 \dots, x = 102.91502 \dots

Solution steps

0 = - 0.01 x^{2} + x + 3

Multiply both sides by

100

0 = - x^{2} + 100 x + 300

Switch sides

- x^{2} + 100 x + 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 1 ) \cdot 300}{2 ( - 1 )}

10 0^{2} - 4 (- 1) \cdot 300 = 407

x_{1, 2} = \frac{- 100 \pm 40 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 100 + 40 7}{2 ( - 1 )}, x_{2} = \frac{- 100 - 40 7}{2 ( - 1 )}

x = \frac{- 100 + 40 7}{2 ( - 1 )} : - 10 (27 - 5)

x = \frac{- 100 - 40 7}{2 ( - 1 )} : 10 (5 + 27)

The solutions to the quadratic equation are:

x = - 10 (27 - 5), x = 10 (5 + 27)

m^{2} = 4

30 b + 6 = 3 b

a x^{3} + b x^{3} - 8 a - 8 b

(m + 2)^{2} - (m + 1)^{2}

f g + f

What are the solutions to the equation 0=-0.01x^2+x+3 ?
The solutions to the equation 0=-0.01x^2+x+3 are x=-10(2sqrt(7)-5),x=10(5+2sqrt(7))
Find the zeros of 0=-0.01x^2+x+3
The zeros of 0=-0.01x^2+x+3 are x=-10(2sqrt(7)-5),x=10(5+2sqrt(7))