What are the solutions to the equation -3x^2-5x+8=0 ?

The solutions to the equation -3x^2-5x+8=0 are x=-8/3 ,x=1

Find the zeros of -3x^2-5x+8=0

The zeros of -3x^2-5x+8=0 are x=-8/3 ,x=1

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- 3 x^{2} - 5 x + 8 = 0

x = - \frac{8}{3}, x = 1

Decimal Notation

x = - 2.66666 \dots, x = 1

Solution steps

- 3 x^{2} - 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

(- 5)^{2} - 4 (- 3) \cdot 8 = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 11}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 11}{2 ( - 3 )} : - \frac{8}{3}

x = \frac{- ( - 5 ) - 11}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = - \frac{8}{3}, x = 1

x^{3} + 8 x^{2} + 6 x + 48

\frac{2 ^{0.0001} - 1}{0.0001}

x - 1 = 2 x + 6

\frac{6}{x - 3} < \frac{3}{x - 7}

7 - ∣ x - 1 ∣ > 4

What are the solutions to the equation -3x^2-5x+8=0 ?
The solutions to the equation -3x^2-5x+8=0 are x=-8/3 ,x=1
Find the zeros of -3x^2-5x+8=0
The zeros of -3x^2-5x+8=0 are x=-8/3 ,x=1