What are the solutions to the equation 3+x=(-2x-1)^2+((x-1)^2)/4 ?

The solutions to the equation 3+x=(-2x-1)^2+((x-1)^2)/4 are x= 7/17 ,x=-1

Find the zeros of 3+x=(-2x-1)^2+((x-1)^2)/4

The zeros of 3+x=(-2x-1)^2+((x-1)^2)/4 are x= 7/17 ,x=-1

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3 + x = (- 2 x - 1)^{2} + \frac{( x - 1 ) ^{2}}{4}

x = \frac{7}{17}, x = - 1

Decimal Notation

x = 0.41176 \dots, x = - 1

Solution steps

3 + x = (- 2 x - 1)^{2} + \frac{( x - 1 ) ^{2}}{4}

Multiply both sides by

4

12 + 4 x = 4 (- 2 x - 1)^{2} + (x - 1)^{2}

Expand

4 (- 2 x - 1)^{2} + (x - 1)^{2} : 17 x^{2} + 14 x + 5

12 + 4 x = 17 x^{2} + 14 x + 5

Switch sides

17 x^{2} + 14 x + 5 = 12 + 4 x

Move

4 x

to the left side

17 x^{2} + 10 x + 5 = 12

Move

12

to the left side

17 x^{2} + 10 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 17 ( - 7 )}{2 \cdot 17}

1 0^{2} - 4 \cdot 17 (- 7) = 24

x_{1, 2} = \frac{- 10 \pm 24}{2 \cdot 17}

Separate the solutions

x_{1} = \frac{- 10 + 24}{2 \cdot 17}, x_{2} = \frac{- 10 - 24}{2 \cdot 17}

x = \frac{- 10 + 24}{2 \cdot 17} : \frac{7}{17}

x = \frac{- 10 - 24}{2 \cdot 17} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{17}, x = - 1

(26)^{2}

- (\frac{1}{3})^{x}

100 0^{- \frac{4}{3}}

\frac{\frac{- 5}{- 2}}{\frac{6}{7}}

(5 - 2 i) + (- 7 + 8 i)

What are the solutions to the equation 3+x=(-2x-1)^2+((x-1)^2)/4 ?
The solutions to the equation 3+x=(-2x-1)^2+((x-1)^2)/4 are x= 7/17 ,x=-1
Find the zeros of 3+x=(-2x-1)^2+((x-1)^2)/4
The zeros of 3+x=(-2x-1)^2+((x-1)^2)/4 are x= 7/17 ,x=-1