What is (2/3 a^m)(3/4 a^2b^4)(-3a^4b^{x+1}) ?

The solution to (2/3 a^m)(3/4 a^2b^4)(-3a^4b^{x+1}) is -(3a^{m+6}b^{x+5})/2

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simplify (2/3 a^m)(3/4 a^2b^4)(-3a^4b^{x+1})

simplify

(\frac{2}{3} a^{m}) (\frac{3}{4} a^{2} b^{4}) (- 3 a^{4} b^{x + 1})

- \frac{3 a ^{m + 6} b ^{x + 5}}{2}

Solution steps

(\frac{2}{3} a^{m}) (\frac{3}{4} a^{2} b^{4}) (- 3 a^{4} b^{x + 1})

Apply rule:

a (- b) = - ab

(\frac{2}{3} a^{m}) (\frac{3}{4} a^{2} b^{4}) (- 3 a^{4} b^{x + 1}) = - \frac{2}{3} a^{m} \frac{3}{4} a^{2} b^{4} \cdot 3 a^{4} b^{x + 1}

= - \frac{2}{3} a^{m} \frac{3}{4} a^{2} b^{4} \cdot 3 a^{4} b^{x + 1}

Simplify

a^{m} a^{2} a^{4} : a^{m + 6}

= - \frac{2}{3} a^{m + 6} \frac{3}{4} b^{4} \cdot 3 b^{x + 1}

Simplify

b^{4} b^{x + 1} : b^{x + 5}

= - \frac{2}{3} a^{m + 6} \frac{3}{4} b^{x + 5} \cdot 3

Simplify

- \frac{2}{3} a^{m + 6} \frac{3}{4} b^{x + 5} \cdot 3 : - \frac{3 a ^{m + 6} b ^{x + 5}}{2}

= - \frac{3 a ^{m + 6} b ^{x + 5}}{2}

- 4 x + \frac{4}{9} = \frac{7}{9}

2 (\frac{5}{3})

2 + (- 3)

x^{2} + 6 x - 1 \geq 3 x - 1

7 (x - 2) - 5 x = - 3 x

What is (2/3 a^m)(3/4 a^2b^4)(-3a^4b^{x+1}) ?
The solution to (2/3 a^m)(3/4 a^2b^4)(-3a^4b^{x+1}) is -(3a^{m+6}b^{x+5})/2