What are the solutions to the equation -4x^2+3x+22=0 ?

The solutions to the equation -4x^2+3x+22=0 are x=-2,x= 11/4

Find the zeros of -4x^2+3x+22=0

The zeros of -4x^2+3x+22=0 are x=-2,x= 11/4

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- 4 x^{2} + 3 x + 22 = 0

x = - 2, x = \frac{11}{4}

Decimal Notation

x = - 2, x = 2.75

Solution steps

- 4 x^{2} + 3 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 22}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 22 = 19

x_{1, 2} = \frac{- 3 \pm 19}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 19}{2 ( - 4 )}, x_{2} = \frac{- 3 - 19}{2 ( - 4 )}

x = \frac{- 3 + 19}{2 ( - 4 )} : - 2

x = \frac{- 3 - 19}{2 ( - 4 )} : \frac{11}{4}

The solutions to the quadratic equation are:

x = - 2, x = \frac{11}{4}

∣ 3 x + 6 ∣ = 9

(1 + \frac{0.09}{2})^{2} - 1

8^{\frac{7}{6}}

1 + \frac{1}{4} r \leq \frac{5}{4} or \frac{3}{2} r + \frac{1}{3} \geq \frac{109}{30}

4 = 268.47 + 117.8 x

What are the solutions to the equation -4x^2+3x+22=0 ?
The solutions to the equation -4x^2+3x+22=0 are x=-2,x= 11/4
Find the zeros of -4x^2+3x+22=0
The zeros of -4x^2+3x+22=0 are x=-2,x= 11/4