What are the solutions to the equation 3x^2+8x-35=0 ?

The solutions to the equation 3x^2+8x-35=0 are x= 7/3 ,x=-5

Find the zeros of 3x^2+8x-35=0

The zeros of 3x^2+8x-35=0 are x= 7/3 ,x=-5

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3 x^{2} + 8 x - 35 = 0

x = \frac{7}{3}, x = - 5

Decimal Notation

x = 2.33333 \dots, x = - 5

Solution steps

3 x^{2} + 8 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 35 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 35) = 22

x_{1, 2} = \frac{- 8 \pm 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 22}{2 \cdot 3}, x_{2} = \frac{- 8 - 22}{2 \cdot 3}

x = \frac{- 8 + 22}{2 \cdot 3} : \frac{7}{3}

x = \frac{- 8 - 22}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 5

- 5 (- 2)

5 \cdot (\frac{1}{2})^{0}

\frac{7 n ^{3}}{2 n ^{5}}

(x^{2} + 1)^{3} + (y^{2} - 1)^{3}

\frac{7 c + 3}{2} \leq - 5

What are the solutions to the equation 3x^2+8x-35=0 ?
The solutions to the equation 3x^2+8x-35=0 are x= 7/3 ,x=-5
Find the zeros of 3x^2+8x-35=0
The zeros of 3x^2+8x-35=0 are x= 7/3 ,x=-5