What are the solutions to the equation 4x^2-8x-2=0 ?

The solutions to the equation 4x^2-8x-2=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

Find the zeros of 4x^2-8x-2=0

The zeros of 4x^2-8x-2=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

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4 x^{2} - 8 x - 2 = 0

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

4 x^{2} - 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 2) = 46

x_{1, 2} = \frac{- ( - 8 ) \pm 4 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 6}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 6}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 6}{2 \cdot 4} : \frac{2 + 6}{2}

x = \frac{- ( - 8 ) - 4 6}{2 \cdot 4} : \frac{2 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

8 b + 5 = 133

\frac{- 1 - ( \frac{- 9}{5} )}{2 - 1}

(x + 3) (x - 1) (4 + x) > 0

x^{2} - 1 0^{6} \cdot 60 \cdot 60 \cdot 24 \cdot 30 \cdot 12 = 0

5 (- 3)

What are the solutions to the equation 4x^2-8x-2=0 ?
The solutions to the equation 4x^2-8x-2=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2
Find the zeros of 4x^2-8x-2=0
The zeros of 4x^2-8x-2=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2