What are the solutions to the equation 25z^2+98=100z ?

The solutions to the equation 25z^2+98=100z are z=(10+sqrt(2))/5 ,z=(10-sqrt(2))/5

Find the zeros of 25z^2+98=100z

The zeros of 25z^2+98=100z are z=(10+sqrt(2))/5 ,z=(10-sqrt(2))/5

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25 z^{2} + 98 = 100 z

z = \frac{10 + 2}{5}, z = \frac{10 - 2}{5}

Decimal Notation

z = 2.28284 \dots, z = 1.71715 \dots

Solution steps

25 z^{2} + 98 = 100 z

Move

100 z

to the left side

25 z^{2} + 98 - 100 z = 0

Write in the standard form

a x^{2} + b x + c = 0

25 z^{2} - 100 z + 98 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 100 ) \pm ( - 100 ) ^{2} - 4 \cdot 25 \cdot 98}{2 \cdot 25}

(- 100)^{2} - 4 \cdot 25 \cdot 98 = 102

z_{1, 2} = \frac{- ( - 100 ) \pm 10 2}{2 \cdot 25}

Separate the solutions

z_{1} = \frac{- ( - 100 ) + 10 2}{2 \cdot 25}, z_{2} = \frac{- ( - 100 ) - 10 2}{2 \cdot 25}

z = \frac{- ( - 100 ) + 10 2}{2 \cdot 25} : \frac{10 + 2}{5}

z = \frac{- ( - 100 ) - 10 2}{2 \cdot 25} : \frac{10 - 2}{5}

The solutions to the quadratic equation are:

z = \frac{10 + 2}{5}, z = \frac{10 - 2}{5}

3 x^{2} + 16 x - 35

\frac{x}{3} \geq - 33

48 + 75

x - 9 \geq - 10

64 x^{2} - 144 x + 81

What are the solutions to the equation 25z^2+98=100z ?
The solutions to the equation 25z^2+98=100z are z=(10+sqrt(2))/5 ,z=(10-sqrt(2))/5
Find the zeros of 25z^2+98=100z
The zeros of 25z^2+98=100z are z=(10+sqrt(2))/5 ,z=(10-sqrt(2))/5