What are the solutions to the equation 6x^2-5x-17=0 ?

The solutions to the equation 6x^2-5x-17=0 are x=(5+sqrt(433))/(12),x=(5-sqrt(433))/(12)

Find the zeros of 6x^2-5x-17=0

The zeros of 6x^2-5x-17=0 are x=(5+sqrt(433))/(12),x=(5-sqrt(433))/(12)

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6 x^{2} - 5 x - 17 = 0

x = \frac{5 + 433}{12}, x = \frac{5 - 433}{12}

Solution steps

6 x^{2} - 5 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 17 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 17) = 433

x_{1, 2} = \frac{- ( - 5 ) \pm 433}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 433}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 433}{2 \cdot 6}

x = \frac{- ( - 5 ) + 433}{2 \cdot 6} : \frac{5 + 433}{12}

x = \frac{- ( - 5 ) - 433}{2 \cdot 6} : \frac{5 - 433}{12}

The solutions to the quadratic equation are:

x = \frac{5 + 433}{12}, x = \frac{5 - 433}{12}

10 x + 25

\frac{9 ^{3}}{9}

(9^{- 3} \cdot 1 6^{\frac{3}{2}})^{\frac{1}{6}}

\frac{4 ^{8}}{4 ^{5}}

2 d^{2} + 11 d + 5

What are the solutions to the equation 6x^2-5x-17=0 ?
The solutions to the equation 6x^2-5x-17=0 are x=(5+sqrt(433))/(12),x=(5-sqrt(433))/(12)
Find the zeros of 6x^2-5x-17=0
The zeros of 6x^2-5x-17=0 are x=(5+sqrt(433))/(12),x=(5-sqrt(433))/(12)