What are the solutions to the equation x^2+(-3/5)^2=1 ?

The solutions to the equation x^2+(-3/5)^2=1 are x= 4/5 ,x=-4/5

Find the zeros of x^2+(-3/5)^2=1

The zeros of x^2+(-3/5)^2=1 are x= 4/5 ,x=-4/5

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x^{2} + (- \frac{3}{5})^{2} = 1

x = \frac{4}{5}, x = - \frac{4}{5}

Solution steps

x^{2} + (- \frac{3}{5})^{2} = 1

Expand

x^{2} + (- \frac{3}{5})^{2} : x^{2} + \frac{9}{25}

x^{2} + \frac{9}{25} = 1

Move

\frac{9}{25}

to the right side

x^{2} = 1 - \frac{9}{25}

Simplify

1 - \frac{9}{25} : \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{25}, x = - \frac{16}{25}

\frac{16}{25} = \frac{4}{5}

- \frac{16}{25} = - \frac{4}{5}

x = \frac{4}{5}, x = - \frac{4}{5}

i z = 4 - z i

20 v^{2} + 3 v - 5 v^{2} - 5 v - 1

\frac{x}{- 6} \geq - 20

\frac{1}{2} x + \frac{1}{8} x = - 1

\frac{1}{3} (x + 3)^{2} - 5 = 4

What are the solutions to the equation x^2+(-3/5)^2=1 ?
The solutions to the equation x^2+(-3/5)^2=1 are x= 4/5 ,x=-4/5
Find the zeros of x^2+(-3/5)^2=1
The zeros of x^2+(-3/5)^2=1 are x= 4/5 ,x=-4/5