What are the solutions to the equation 5x^2+9=4 ?

The solutions to the equation 5x^2+9=4 are x=i,x=-i

Find the zeros of 5x^2+9=4

The zeros of 5x^2+9=4 are x=i,x=-i

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5 x^{2} + 9 = 4

x = i, x = - i

Solution steps

5 x^{2} + 9 = 4

Move

9

to the right side

5 x^{2} = - 5

Divide both sides by

5

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

- x^{2} + 11 = 0

\frac{4 + i}{2 - 5 i}

\frac{18 x ^{7} y ^{8}}{30 x ^{6} y ^{6}}

(- 32)^{\frac{3}{5}}

21 k^{2} + 20 k - 32 = - 7

What are the solutions to the equation 5x^2+9=4 ?
The solutions to the equation 5x^2+9=4 are x=i,x=-i
Find the zeros of 5x^2+9=4
The zeros of 5x^2+9=4 are x=i,x=-i