What are the solutions to the equation 0=-(x+1)^2 ?

The solutions to the equation 0=-(x+1)^2 are x=-1

Find the zeros of 0=-(x+1)^2

The zeros of 0=-(x+1)^2 are x=-1

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0 = - (x + 1)^{2}

x = - 1

Solution steps

0 = - (x + 1)^{2}

Switch sides

- (x + 1)^{2} = 0

Divide both sides by

- 1

(x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 1 = 0 : x = - 1

The solution to the quadratic equation is:

x = - 1

\frac{3}{5} ab + \frac{1}{10} ab

(x - 1)^{2} = (2 x + 6)

∣ 9 - 2 x ∣ \geq ∣ 4 x ∣

2 t + 2 > 10

∣ 2 x + 8 ∣ > 6

What are the solutions to the equation 0=-(x+1)^2 ?
The solutions to the equation 0=-(x+1)^2 are x=-1
Find the zeros of 0=-(x+1)^2
The zeros of 0=-(x+1)^2 are x=-1