What are the solutions to the equation z^2-8z=0 ?

The solutions to the equation z^2-8z=0 are z=8,z=0

Find the zeros of z^2-8z=0

The zeros of z^2-8z=0 are z=8,z=0

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z^{2} - 8 z = 0

z = 8, z = 0

Solution steps

z^{2} - 8 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

z_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, z_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

z = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

z = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

z = 8, z = 0

\frac{1}{2} ∣ x ∣ - 4 = 4

54 x + 12 x^{2} - 2 x^{3}

\frac{8}{3} - \frac{1}{3}

m^{2} - mn - 20 n^{2}

\frac{h}{9} = 7

What are the solutions to the equation z^2-8z=0 ?
The solutions to the equation z^2-8z=0 are z=8,z=0
Find the zeros of z^2-8z=0
The zeros of z^2-8z=0 are z=8,z=0