What are the solutions to the equation 16x^2-22x+5=2x ?

The solutions to the equation 16x^2-22x+5=2x are x= 5/4 ,x= 1/4

Find the zeros of 16x^2-22x+5=2x

The zeros of 16x^2-22x+5=2x are x= 5/4 ,x= 1/4

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16 x^{2} - 22 x + 5 = 2 x

x = \frac{5}{4}, x = \frac{1}{4}

Decimal Notation

x = 1.25, x = 0.25

Solution steps

16 x^{2} - 22 x + 5 = 2 x

Move

2 x

to the left side

16 x^{2} - 24 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 5}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 5 = 16

x_{1, 2} = \frac{- ( - 24 ) \pm 16}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 16}{2 \cdot 16}, x_{2} = \frac{- ( - 24 ) - 16}{2 \cdot 16}

x = \frac{- ( - 24 ) + 16}{2 \cdot 16} : \frac{5}{4}

x = \frac{- ( - 24 ) - 16}{2 \cdot 16} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{1}{4}

2^{\frac{5}{2}}

16 = - 2 x

(4 - 5 x)^{3} - 7 (4 - 5 x)^{2} (x + 1)

k^{2} + k

(0 + 4)^{2} + (y + 5)^{2} = 81

What are the solutions to the equation 16x^2-22x+5=2x ?
The solutions to the equation 16x^2-22x+5=2x are x= 5/4 ,x= 1/4
Find the zeros of 16x^2-22x+5=2x
The zeros of 16x^2-22x+5=2x are x= 5/4 ,x= 1/4