What is ((9+5i)/(3-2i))^2 ?

The solution to ((9+5i)/(3-2i))^2 is ((17+33i)^2)/(169)

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simplify ((9+5i)/(3-2i))^2

simplify

(\frac{9 + 5 i}{3 - 2 i})^{2}

\frac{( 17 + 33 i ) ^{2}}{169}

Solution steps

(\frac{9 + 5 i}{3 - 2 i})^{2}

Simplify

\frac{9 + 5 i}{3 - 2 i} : \frac{17}{13} + \frac{33}{13} i

= (\frac{17}{13} + \frac{33}{13} i)^{2}

Multiply

\frac{33}{13} i : \frac{33 i}{13}

= (\frac{17}{13} + \frac{33 i}{13})^{2}

Combine the fractions

\frac{17}{13} + \frac{33 i}{13} : \frac{17 + 33 i}{13}

= (\frac{17 + 33 i}{13})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 17 + 33 i ) ^{2}}{1 3 ^{2}}

1 3^{2} = 169

= \frac{( 17 + 33 i ) ^{2}}{169}

72 + 32 + 18

m^{2} - 10 m + 9

\frac{a}{3} = \frac{a - 3}{2}

lo g_{2} (\frac{1}{16}) = x

8 - 5 x = 6

What is ((9+5i)/(3-2i))^2 ?
The solution to ((9+5i)/(3-2i))^2 is ((17+33i)^2)/(169)