What are the solutions to the equation 2x^2-36=x ?

The solutions to the equation 2x^2-36=x are x= 9/2 ,x=-4

Find the zeros of 2x^2-36=x

The zeros of 2x^2-36=x are x= 9/2 ,x=-4

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2 x^{2} - 36 = x

x = \frac{9}{2}, x = - 4

Solution steps

2 x^{2} - 36 = x

Move

x

to the left side

2 x^{2} - 36 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 36 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 36) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 2}

x = \frac{- ( - 1 ) + 17}{2 \cdot 2} : \frac{9}{2}

x = \frac{- ( - 1 ) - 17}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 4

9 x^{2} + 9 x + 52 = 0

(5 a^{3} b)^{4}

∣ x - 1 ∣ < 9

9 - 2 x^{2} = - 17

\frac{0.628 2 ^{2}}{2 \cdot 0.293}

What are the solutions to the equation 2x^2-36=x ?
The solutions to the equation 2x^2-36=x are x= 9/2 ,x=-4
Find the zeros of 2x^2-36=x
The zeros of 2x^2-36=x are x= 9/2 ,x=-4