What are the solutions to the equation (2x-5)^2=9 ?

The solutions to the equation (2x-5)^2=9 are x=4,x=1

Find the zeros of (2x-5)^2=9

The zeros of (2x-5)^2=9 are x=4,x=1

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(2 x - 5)^{2} = 9

x = 4, x = 1

Solution steps

(2 x - 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 9 : x = 4

Solve

2 x - 5 = - 9 : x = 1

The solutions to the quadratic equation are:

x = 4, x = 1

6 x^{2} - 33 x - 120

- \frac{2 ( - 1 )}{( 1 + ( - 1 ) ^{2} ) ^{2}}

\frac{7}{12} + \frac{1}{4} + \frac{3}{8}

5 x + 16 = 56

\frac{b}{5} = \frac{2}{3}

What are the solutions to the equation (2x-5)^2=9 ?
The solutions to the equation (2x-5)^2=9 are x=4,x=1
Find the zeros of (2x-5)^2=9
The zeros of (2x-5)^2=9 are x=4,x=1