What are the solutions to the equation w(7w-10)+4=0 ?

The solutions to the equation w(7w-10)+4=0 are w= 5/7+i(sqrt(3))/7 ,w= 5/7-i(sqrt(3))/7

Find the zeros of w(7w-10)+4=0

The zeros of w(7w-10)+4=0 are w= 5/7+i(sqrt(3))/7 ,w= 5/7-i(sqrt(3))/7

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w (7 w - 10) + 4 = 0

w = \frac{5}{7} + i \frac{3}{7}, w = \frac{5}{7} - i \frac{3}{7}

Solution steps

w (7 w - 10) + 4 = 0

Expand

w (7 w - 10) + 4 : 7 w^{2} - 10 w + 4

7 w^{2} - 10 w + 4 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 7 \cdot 4}{2 \cdot 7}

Simplify

(- 10)^{2} - 4 \cdot 7 \cdot 4 : 23 i

w_{1, 2} = \frac{- ( - 10 ) \pm 2 3 i}{2 \cdot 7}

Separate the solutions

w_{1} = \frac{- ( - 10 ) + 2 3 i}{2 \cdot 7}, w_{2} = \frac{- ( - 10 ) - 2 3 i}{2 \cdot 7}

w = \frac{- ( - 10 ) + 2 3 i}{2 \cdot 7} : \frac{5}{7} + i \frac{3}{7}

w = \frac{- ( - 10 ) - 2 3 i}{2 \cdot 7} : \frac{5}{7} - i \frac{3}{7}

The solutions to the quadratic equation are:

w = \frac{5}{7} + i \frac{3}{7}, w = \frac{5}{7} - i \frac{3}{7}

\frac{11}{8} t - (\frac{7}{8} + \frac{3}{8} t) = 0

3 a^{2} + 6 a

\frac{1}{8} x + 10 \geq \frac{1}{4} x - 5

\frac{x}{x ^{2} y ^{4} y ^{- 4}}

\frac{3}{2} t^{2} - 45 t - 45 = 0

What are the solutions to the equation w(7w-10)+4=0 ?
The solutions to the equation w(7w-10)+4=0 are w= 5/7+i(sqrt(3))/7 ,w= 5/7-i(sqrt(3))/7
Find the zeros of w(7w-10)+4=0
The zeros of w(7w-10)+4=0 are w= 5/7+i(sqrt(3))/7 ,w= 5/7-i(sqrt(3))/7