What are the solutions to the equation x^2-5x+630=0 ?

The solutions to the equation x^2-5x+630=0 are x= 5/2+i(sqrt(2495))/2 ,x= 5/2-i(sqrt(2495))/2

Find the zeros of x^2-5x+630=0

The zeros of x^2-5x+630=0 are x= 5/2+i(sqrt(2495))/2 ,x= 5/2-i(sqrt(2495))/2

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x^{2} - 5 x + 630 = 0

x = \frac{5}{2} + i \frac{2495}{2}, x = \frac{5}{2} - i \frac{2495}{2}

Solution steps

x^{2} - 5 x + 630 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 630}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 630 : 2495 i

x_{1, 2} = \frac{- ( - 5 ) \pm 2495 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 2495 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 2495 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 2495 i}{2 \cdot 1} : \frac{5}{2} + i \frac{2495}{2}

x = \frac{- ( - 5 ) - 2495 i}{2 \cdot 1} : \frac{5}{2} - i \frac{2495}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{2495}{2}, x = \frac{5}{2} - i \frac{2495}{2}

∣ 2 x - 5 ∣ \geq 2

2 (8)^{\frac{2}{3}}

4 (x + 1) - 3 = 4 x + 1

121 x^{4} y^{4} - 1

2 (\frac{4}{5})^{0}

What are the solutions to the equation x^2-5x+630=0 ?
The solutions to the equation x^2-5x+630=0 are x= 5/2+i(sqrt(2495))/2 ,x= 5/2-i(sqrt(2495))/2
Find the zeros of x^2-5x+630=0
The zeros of x^2-5x+630=0 are x= 5/2+i(sqrt(2495))/2 ,x= 5/2-i(sqrt(2495))/2