What are the solutions to the equation 16y^2+0y+10=0 ?

The solutions to the equation 16y^2+0y+10=0 are y=i(sqrt(10))/4 ,y=-i(sqrt(10))/4

Find the zeros of 16y^2+0y+10=0

The zeros of 16y^2+0y+10=0 are y=i(sqrt(10))/4 ,y=-i(sqrt(10))/4

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16 y^{2} + 0 y + 10 = 0

y = i \frac{10}{4}, y = - i \frac{10}{4}

Solution steps

16 y^{2} + 0 \cdot y + 10 = 0

Refine

16 y^{2} + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 16 \cdot 10}{2 \cdot 16}

Simplify

0^{2} - 4 \cdot 16 \cdot 10 : 810 i

y_{1, 2} = \frac{- 0 \pm 8 10 i}{2 \cdot 16}

Separate the solutions

y_{1} = \frac{- 0 + 8 10 i}{2 \cdot 16}, y_{2} = \frac{- 0 - 8 10 i}{2 \cdot 16}

y = \frac{- 0 + 8 10 i}{2 \cdot 16} : i \frac{10}{4}

y = \frac{- 0 - 8 10 i}{2 \cdot 16} : - i \frac{10}{4}

The solutions to the quadratic equation are:

y = i \frac{10}{4}, y = - i \frac{10}{4}

x (x - 1) - 2 x = - 6 x

5 x^{2} + 12 x + 7

(500 \cdot 10 \cdot 70) = (500 \cdot 10 \cdot 30) + (\frac{1}{2} \cdot 500 \cdot x^{2})

- (4 x + 2) - 7 x = - 12 x + 1

4 x^{2} + 3 x + 3 = 0

What are the solutions to the equation 16y^2+0y+10=0 ?
The solutions to the equation 16y^2+0y+10=0 are y=i(sqrt(10))/4 ,y=-i(sqrt(10))/4
Find the zeros of 16y^2+0y+10=0
The zeros of 16y^2+0y+10=0 are y=i(sqrt(10))/4 ,y=-i(sqrt(10))/4