What are the solutions to the equation 10x^2+4x+5=0 ?

The solutions to the equation 10x^2+4x+5=0 are x=-1/5+i(sqrt(46))/(10),x=-1/5-i(sqrt(46))/(10)

Find the zeros of 10x^2+4x+5=0

The zeros of 10x^2+4x+5=0 are x=-1/5+i(sqrt(46))/(10),x=-1/5-i(sqrt(46))/(10)

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10 x^{2} + 4 x + 5 = 0

x = - \frac{1}{5} + i \frac{46}{10}, x = - \frac{1}{5} - i \frac{46}{10}

Solution steps

10 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 10 \cdot 5}{2 \cdot 10}

Simplify

4^{2} - 4 \cdot 10 \cdot 5 : 246 i

x_{1, 2} = \frac{- 4 \pm 2 46 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 4 + 2 46 i}{2 \cdot 10}, x_{2} = \frac{- 4 - 2 46 i}{2 \cdot 10}

x = \frac{- 4 + 2 46 i}{2 \cdot 10} : - \frac{1}{5} + i \frac{46}{10}

x = \frac{- 4 - 2 46 i}{2 \cdot 10} : - \frac{1}{5} - i \frac{46}{10}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{46}{10}, x = - \frac{1}{5} - i \frac{46}{10}

0 = 2 x - 1

0 = ln y^{2} - y

(11 i) (- 4 i)

5 \cdot 45

3 x^{2} - 8 x + 4 > 0

What are the solutions to the equation 10x^2+4x+5=0 ?
The solutions to the equation 10x^2+4x+5=0 are x=-1/5+i(sqrt(46))/(10),x=-1/5-i(sqrt(46))/(10)
Find the zeros of 10x^2+4x+5=0
The zeros of 10x^2+4x+5=0 are x=-1/5+i(sqrt(46))/(10),x=-1/5-i(sqrt(46))/(10)