What are the solutions to the equation 0=x^2-2x-63 ?

The solutions to the equation 0=x^2-2x-63 are x=9,x=-7

Find the zeros of 0=x^2-2x-63

The zeros of 0=x^2-2x-63 are x=9,x=-7

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0 = x^{2} - 2 x - 63

x = 9, x = - 7

Solution steps

0 = x^{2} - 2 x - 63

Switch sides

x^{2} - 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- ( - 2 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 16}{2 \cdot 1}

x = \frac{- ( - 2 ) + 16}{2 \cdot 1} : 9

x = \frac{- ( - 2 ) - 16}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 9, x = - 7

(x^{2} + 1)^{\frac{1}{2}} + 2 (x^{2} + 1)^{- \frac{1}{2}}

2 x^{4} - x^{3} - 9 x^{2} + 4 x + 4

3 (4 x - 1)^{2} - 7 (4 x - 1) = - 4

4 - 2 x < 3 (3 - x)

X^{4} - Y^{4}

What are the solutions to the equation 0=x^2-2x-63 ?
The solutions to the equation 0=x^2-2x-63 are x=9,x=-7
Find the zeros of 0=x^2-2x-63
The zeros of 0=x^2-2x-63 are x=9,x=-7