What are the solutions to the equation 2x^2-13x+14=0 ?

The solutions to the equation 2x^2-13x+14=0 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4

Find the zeros of 2x^2-13x+14=0

The zeros of 2x^2-13x+14=0 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4

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2 x^{2} - 13 x + 14 = 0

x = \frac{13 + 57}{4}, x = \frac{13 - 57}{4}

Decimal Notation

x = 5.13745 \dots, x = 1.36254 \dots

Solution steps

2 x^{2} - 13 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 \cdot 14 = 57

x_{1, 2} = \frac{- ( - 13 ) \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 57}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 57}{2 \cdot 2}

x = \frac{- ( - 13 ) + 57}{2 \cdot 2} : \frac{13 + 57}{4}

x = \frac{- ( - 13 ) - 57}{2 \cdot 2} : \frac{13 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{13 + 57}{4}, x = \frac{13 - 57}{4}

192 x^{2} - 243 y^{3}

2 0^{2}

x y^{3} + y

\frac{1}{2} y^{2} - \frac{5}{2} y - 7

∣ 4 ∣ - 9

What are the solutions to the equation 2x^2-13x+14=0 ?
The solutions to the equation 2x^2-13x+14=0 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4
Find the zeros of 2x^2-13x+14=0
The zeros of 2x^2-13x+14=0 are x=(13+sqrt(57))/4 ,x=(13-sqrt(57))/4