What are the solutions to the equation z^2+8=9z ?

The solutions to the equation z^2+8=9z are z=8,z=1

Find the zeros of z^2+8=9z

The zeros of z^2+8=9z are z=8,z=1

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z^{2} + 8 = 9 z

z = 8, z = 1

Solution steps

z^{2} + 8 = 9 z

Move

9 z

to the left side

z^{2} + 8 - 9 z = 0

Write in the standard form

a x^{2} + b x + c = 0

z^{2} - 9 z + 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

z_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, z_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

z = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

z = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

z = 8, z = 1

\frac{5}{7} = p + \frac{4}{7}

\frac{49}{9}

- 3 \leq x

x^{2} + 3 x - 9 = 9

x^{2} + 8 x + 15

What are the solutions to the equation z^2+8=9z ?
The solutions to the equation z^2+8=9z are z=8,z=1
Find the zeros of z^2+8=9z
The zeros of z^2+8=9z are z=8,z=1