What are the solutions to the equation 4x^2+4x-15=0 ?

The solutions to the equation 4x^2+4x-15=0 are x= 3/2 ,x=-5/2

Find the zeros of 4x^2+4x-15=0

The zeros of 4x^2+4x-15=0 are x= 3/2 ,x=-5/2

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4 x^{2} + 4 x - 15 = 0

x = \frac{3}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.5, x = - 2.5

Solution steps

4 x^{2} + 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 15) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 4}, x_{2} = \frac{- 4 - 16}{2 \cdot 4}

x = \frac{- 4 + 16}{2 \cdot 4} : \frac{3}{2}

x = \frac{- 4 - 16}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{5}{2}

(8 + 9 i) (8 - 9 i)

2 x^{2} + 1 x - 3

x - 6 = 0

5 x (2 - x) + 4 x (2 x - 5) - (3 x - 4)

- 5 (t - 3) \leq 35

What are the solutions to the equation 4x^2+4x-15=0 ?
The solutions to the equation 4x^2+4x-15=0 are x= 3/2 ,x=-5/2
Find the zeros of 4x^2+4x-15=0
The zeros of 4x^2+4x-15=0 are x= 3/2 ,x=-5/2