What are the solutions to the equation u^2+6u-16=0 ?

The solutions to the equation u^2+6u-16=0 are u=2,u=-8

Find the zeros of u^2+6u-16=0

The zeros of u^2+6u-16=0 are u=2,u=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} + 6 u - 16 = 0

u = 2, u = - 8

Solution steps

u^{2} + 6 u - 16 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

u_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 6 + 10}{2 \cdot 1}, u_{2} = \frac{- 6 - 10}{2 \cdot 1}

u = \frac{- 6 + 10}{2 \cdot 1} : 2

u = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

u = 2, u = - 8

- 1 > \frac{p}{2} + 1

\frac{2}{3} - \frac{1}{9}

5 \cdot \frac{3}{4}

\frac{n}{2 n + 1} + \frac{1}{4 ( n + 1 ) ^{2} - 1}

0 = 4.811 t^{2} - 4.3 t + 24.725

What are the solutions to the equation u^2+6u-16=0 ?
The solutions to the equation u^2+6u-16=0 are u=2,u=-8
Find the zeros of u^2+6u-16=0
The zeros of u^2+6u-16=0 are u=2,u=-8