What are the solutions to the equation w^2=4 ?

The solutions to the equation w^2=4 are w=2,w=-2

Find the zeros of w^2=4

The zeros of w^2=4 are w=2,w=-2

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w^{2} = 4

w = 2, w = - 2

Solution steps

w^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = 4, w = - 4

4 = 2

- 4 = - 2

w = 2, w = - 2

i^{2} = 1

(2 x + y)^{2} - 9 (2 x + y) + 20

\frac{π}{2} \cdot π

\frac{1}{2} \cdot \frac{5}{2}

24 j - 16

What are the solutions to the equation w^2=4 ?
The solutions to the equation w^2=4 are w=2,w=-2
Find the zeros of w^2=4
The zeros of w^2=4 are w=2,w=-2