What are the solutions to the equation 3x^2+25x-8.3=0 ?

The solutions to the equation 3x^2+25x-8.3=0 are x=(-125+sqrt(18115))/(30),x=-(125+sqrt(18115))/(30)

Find the zeros of 3x^2+25x-8.3=0

The zeros of 3x^2+25x-8.3=0 are x=(-125+sqrt(18115))/(30),x=-(125+sqrt(18115))/(30)

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3 x^{2} + 25 x - 8.3 = 0

x = \frac{- 125 + 18115}{30}, x = - \frac{125 + 18115}{30}

Decimal Notation

x = 0.31973 \dots, x = - 8.65306 \dots

Solution steps

3 x^{2} + 25 x - 8.3 = 0

Multiply both sides by

10

30 x^{2} + 250 x - 83 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 250 \pm 25 0 ^{2} - 4 \cdot 30 ( - 83 )}{2 \cdot 30}

25 0^{2} - 4 \cdot 30 (- 83) = 218115

x_{1, 2} = \frac{- 250 \pm 2 18115}{2 \cdot 30}

Separate the solutions

x_{1} = \frac{- 250 + 2 18115}{2 \cdot 30}, x_{2} = \frac{- 250 - 2 18115}{2 \cdot 30}

x = \frac{- 250 + 2 18115}{2 \cdot 30} : \frac{- 125 + 18115}{30}

x = \frac{- 250 - 2 18115}{2 \cdot 30} : - \frac{125 + 18115}{30}

The solutions to the quadratic equation are:

x = \frac{- 125 + 18115}{30}, x = - \frac{125 + 18115}{30}

4 c^{2} + 15 c + 4 = 0

∣ 2 x - 3 ∣ \geq 2

∣ 1 - x ∣ = x - 1

4 (u - 1) - 1 = 2 (2 u - 3)

- 90 > - 5 (k - 3)

What are the solutions to the equation 3x^2+25x-8.3=0 ?
The solutions to the equation 3x^2+25x-8.3=0 are x=(-125+sqrt(18115))/(30),x=-(125+sqrt(18115))/(30)
Find the zeros of 3x^2+25x-8.3=0
The zeros of 3x^2+25x-8.3=0 are x=(-125+sqrt(18115))/(30),x=-(125+sqrt(18115))/(30)