What are the solutions to the equation 0=x^2+4x+2 ?

The solutions to the equation 0=x^2+4x+2 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of 0=x^2+4x+2

The zeros of 0=x^2+4x+2 are x=-2+sqrt(2),x=-2-sqrt(2)

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0 = x^{2} + 4 x + 2

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

0 = x^{2} + 4 x + 2

Switch sides

x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

x = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

x = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

5 x + 15 + x y + 3 y

x^{- \frac{1}{2}} \cdot x^{\frac{1}{2}}

2 x - \frac{1 - 3 x}{10} - \frac{2}{3} = 2 \cdot (x - 3) + \frac{1}{5}

6 v^{2} + 66 v + 60

1 - 125 n^{3}

What are the solutions to the equation 0=x^2+4x+2 ?
The solutions to the equation 0=x^2+4x+2 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of 0=x^2+4x+2
The zeros of 0=x^2+4x+2 are x=-2+sqrt(2),x=-2-sqrt(2)