What are the solutions to the equation -9x^2+6x-1=0 ?

The solutions to the equation -9x^2+6x-1=0 are x= 1/3

Find the zeros of -9x^2+6x-1=0

The zeros of -9x^2+6x-1=0 are x= 1/3

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- 9 x^{2} + 6 x - 1 = 0

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

- 9 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 9 ) ( - 1 )}{2 ( - 9 )}

6^{2} - 4 (- 9) (- 1) = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 ( - 9 )}

x = \frac{- 6}{2 ( - 9 )}

\frac{- 6}{2 ( - 9 )} = \frac{1}{3}

x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

- 14 x^{2} + 7 x^{4}

6 x \leq 24

\frac{\frac{1}{4} b - 1}{5} b > \frac{3}{10} b - \frac{1}{2}

∣ 3 d ∣ + 6 = 15

(8 a^{- 6})^{- \frac{2}{3}}

What are the solutions to the equation -9x^2+6x-1=0 ?
The solutions to the equation -9x^2+6x-1=0 are x= 1/3
Find the zeros of -9x^2+6x-1=0
The zeros of -9x^2+6x-1=0 are x= 1/3