What are the solutions to the equation (4x+7)^2=36 ?

The solutions to the equation (4x+7)^2=36 are x=-1/4 ,x=-13/4

Find the zeros of (4x+7)^2=36

The zeros of (4x+7)^2=36 are x=-1/4 ,x=-13/4

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(4 x + 7)^{2} = 36

x = - \frac{1}{4}, x = - \frac{13}{4}

Decimal Notation

x = - 0.25, x = - 3.25

Solution steps

(4 x + 7)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 7 = 36 : x = - \frac{1}{4}

Solve

4 x + 7 = - 36 : x = - \frac{13}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{13}{4}

(\frac{3 x ^{5} y ^{4}}{x ^{0} y ^{- 3}})^{2}

\frac{5}{6} \cdot 4

7 \leq 2 x

\frac{3}{8} - (- \frac{1}{12})

2 x - 6 + 3 x \geq 8 x + 21

What are the solutions to the equation (4x+7)^2=36 ?
The solutions to the equation (4x+7)^2=36 are x=-1/4 ,x=-13/4
Find the zeros of (4x+7)^2=36
The zeros of (4x+7)^2=36 are x=-1/4 ,x=-13/4