What is 9^{x^2}<= 27^{x^{2-2}} ?

The solution to 9^{x^2}<= 27^{x^{2-2}} is -sqrt(3/2)<= x<= sqrt(3/2)

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9^{x^2}<= 27^{x^{2-2}}

9^{x^{2}} \leq 2 7^{x^{2 - 2}}

- \frac{3}{2} \leq x \leq \frac{3}{2}

Interval Notation

[- \frac{3}{2}, \frac{3}{2}]

Decimal Notation

- 1.22474 \dots \leq x \leq 1.22474 \dots

Solution steps

9^{x^{2}} \leq 2 7^{x^{2 - 2}}

Apply exponent rules

2 x^{2} \leq 3 x^{2 - 2}

Simplify

2 x^{2} \leq 3

2 x^{2} \leq 3 : - \frac{3}{2} \leq x \leq \frac{3}{2}

- \frac{3}{2} \leq x \leq \frac{3}{2}

2 c^{2} - 6 c - 2 = 3 c

∣ 8 - 9 x ∣ = 8

\frac{- 3}{1 - x} < 7

3 + 5 x = 23

k^{2} - 8 k

What is 9^{x^2}<= 27^{x^{2-2}} ?
The solution to 9^{x^2}<= 27^{x^{2-2}} is -sqrt(3/2)<= x<= sqrt(3/2)